LOW-COST HEARING AID

Commercially available hearing aids are quite costly. Here is an inexpensive
hearing aid circuit that uses just four transistors and a few passive components.
Likely :-
  • Ear phone,
  • Mic
  • Resistor and capacitor
  • ON OFF switch           
On moving power switch S to ‘on’ position, the condenser microphone detects the
sound signal, which is amplified by transistors T1 and T2. Now the amplified signal
passes through coupling capacitor C3 to the base of transistor T3. The signal is further
amplified by pnp transistor T4 to drive a low impedance
earphone.
Capacitors C4 and C5 are the power supply decoupling capacitors.
The circuit can be easily assembled on a small, general-purpose PCB or a
Vero board. It operates off a 3V DC supply. For this, you may use two small 1.5V
cells. Keep switch S to ‘off’ state when the circuit is not in use. To increase the
sensitivity of the condenser microphone, house it inside a small tube.
Cost:-
This circuit costs around Rs 65.
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4 comments:

  1. providing circuit is not enough.........need some more explanation for this circuit.......... suddenly they have used pnp transistor without explaining properly........... how pnp drives the ear phone

    ReplyDelete
  2. Isn't this what we learn in Tech. College ? That's why i publish only project. My motto is to provide project....

    ReplyDelete
  3. which software you used for testing circuit?

    ReplyDelete

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